update default method to check if element displayed to always return … #83
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…a boolean and handle exceptions
| } catch (Exception e) { | ||
| //ignore and return false to indicate element is not visible. | ||
| } | ||
| return false; |
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Here you're presuming that if element isn't found (this is when exception is thrown), then it's invisible. But this is hiding that fact (that element wasn't found) from the developer who runs the tests and therefore I think it's not the right way to handle this.
Instead you should be catching that exception in place where you call isDisplayed method.
|
test this please |
…d to always return and added unit test
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I think it would be better to add separate method for that. See PR #91. |
| @@ -208,7 +208,12 @@ public WebElement findElement(By by) { | |||
| */ | |||
| @Override | |||
| public boolean isDisplayed() { | |||
| return wrappedElement.isDisplayed(); | |||
| try{ | |||
| return getWrappedElement().isDisplayed(); | |||
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Either log or rethrow this exception. 
|
SonarQube analysis reported 2 issues:
Watch the comments in this conversation to review them. |
| return getWrappedElement().isDisplayed(); | ||
| try{ | ||
| return getWrappedElement().isDisplayed(); | ||
| } catch (Exception e) { |
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Either log or rethrow this exception.
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…a boolean and handle exceptions