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Dutch flag algo #594

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46 changes: 46 additions & 0 deletions Algorithms/DutchNationalFlagAlgo.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,46 @@
import java.util.Scanner;
public class DutchNationalFlagAlgo
{
public static void sortColors(int[] nums) {
int mid=0;
int low=0;
int high=nums.length - 1;
while(mid<=high)
{
if(nums[mid]==0)
{
int temp = nums[low];
nums[low] = nums[mid];
nums[mid] = temp;
mid++;
low++;
}
else if (nums[mid]==1)
{
mid++;
}
else
{
int temp = nums[high];
nums[high] = nums[mid];
nums[mid] = temp;
high--;
}
}
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int []arr = new int[n];
for(int i=0;i<n;i++)
{
arr[i] = sc.nextInt();
}
sortColors(arr);
for(int i=0;i<n;i++)
{
System.out.print(arr[i]+" ");
}

}
}
44 changes: 44 additions & 0 deletions Algorithms/RecursiveBinarySearch.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,44 @@
// Java implementation of recursive Binary Search
class RecursiveBinarySearch {
// Returns index of x if it is present in arr[l..
// r], else return -1
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r - l) / 2;

// If the element is present at the
// middle itself
if (arr[mid] == x)
return mid;

// If element is smaller than mid, then
// it can only be present in left subarray
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);

// Else the element can only be present
// in right subarray
return binarySearch(arr, mid + 1, r, x);
}

// We reach here when element is not present
// in array
return -1;
}


public static void main(String args[])
{
BinarySearch ob = new BinarySearch();
int arr[] = { 2, 3, 4, 10, 40 };
int n = arr.length;
int x = 10;
int result = ob.binarySearch(arr, 0, n - 1, x);
if (result == -1)
System.out.println("Element not present");
else
System.out.println("Element found at index " + result);
}
}