Added Dijkstra's algo and Fibonacci Search codes!

Dijkstra Algorith.txt

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+// A C++ program for Dijkstra's single source shortest path algorithm. 
+// The program is for adjacency matrix representation of the graph 
+
+#include <limits.h> 
+#include <stdio.h> 
+
+// Number of vertices in the graph 
+#define V 9 
+
+// A utility function to find the vertex with minimum distance value, from 
+// the set of vertices not yet included in shortest path tree 
+int minDistance(int dist[], bool sptSet[]) 
+{ 
+    // Initialize min value 
+    int min = INT_MAX, min_index; 
+
+    for (int v = 0; v < V; v++) 
+        if (sptSet[v] == false && dist[v] <= min) 
+            min = dist[v], min_index = v; 
+
+    return min_index; 
+} 
+
+// A utility function to print the constructed distance array 
+void printSolution(int dist[]) 
+{ 
+    printf("Vertex \t\t Distance from Source\n"); 
+    for (int i = 0; i < V; i++) 
+        printf("%d \t\t %d\n", i, dist[i]); 
+} 
+
+// Function that implements Dijkstra's single source shortest path algorithm 
+// for a graph represented using adjacency matrix representation 
+void dijkstra(int graph[V][V], int src) 
+{ 
+    int dist[V]; // The output array.  dist[i] will hold the shortest 
+    // distance from src to i 
+
+    bool sptSet[V]; // sptSet[i] will be true if vertex i is included in shortest 
+    // path tree or shortest distance from src to i is finalized 
+
+    // Initialize all distances as INFINITE and stpSet[] as false 
+    for (int i = 0; i < V; i++) 
+        dist[i] = INT_MAX, sptSet[i] = false; 
+
+    // Distance of source vertex from itself is always 0 
+    dist[src] = 0; 
+
+    // Find shortest path for all vertices 
+    for (int count = 0; count < V - 1; count++) { 
+        // Pick the minimum distance vertex from the set of vertices not 
+        // yet processed. u is always equal to src in the first iteration. 
+        int u = minDistance(dist, sptSet); 
+
+        // Mark the picked vertex as processed 
+        sptSet[u] = true; 
+
+        // Update dist value of the adjacent vertices of the picked vertex. 
+        for (int v = 0; v < V; v++) 
+
+            // Update dist[v] only if is not in sptSet, there is an edge from 
+            // u to v, and total weight of path from src to  v through u is 
+            // smaller than current value of dist[v] 
+            if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX 
+                && dist[u] + graph[u][v] < dist[v]) 
+                dist[v] = dist[u] + graph[u][v]; 
+    } 
+
+    // print the constructed distance array 
+    printSolution(dist); 
+} 
+
+// driver program to test above function 
+int main() 
+{ 
+    /* Let us create the example graph discussed above */
+    int graph[V][V] = { { 0, 4, 0, 0, 0, 0, 0, 8, 0 }, 
+                        { 4, 0, 8, 0, 0, 0, 0, 11, 0 }, 
+                        { 0, 8, 0, 7, 0, 4, 0, 0, 2 }, 
+                        { 0, 0, 7, 0, 9, 14, 0, 0, 0 }, 
+                        { 0, 0, 0, 9, 0, 10, 0, 0, 0 }, 
+                        { 0, 0, 4, 14, 10, 0, 2, 0, 0 }, 
+                        { 0, 0, 0, 0, 0, 2, 0, 1, 6 }, 
+                        { 8, 11, 0, 0, 0, 0, 1, 0, 7 }, 
+                        { 0, 0, 2, 0, 0, 0, 6, 7, 0 } }; 
+
+    dijkstra(graph, 0); 
+
+    return 0; 
+} 

FibonacciSearch.txt

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+#include<iostream>
+using namespace std;
+
+void FibonacciSearch(int *a, int start, int end, int *fib, int index, int item) 
+{
+   	int i, mid;
+   	mid = start+fib[index-2];
+   	if(item == a[mid]) 
+	{	cout<<"\n item found at "<<mid<<" index.";
+     		return;
+   	} 
+	else if(item == a[start]) 
+	{	cout<<"\n item found at "<<start<<" index.";
+      		return;
+   	} 
+	else if(item == a[end]) 
+	{	cout<<"\n item found at "<<end<<" index.";
+      		return;
+   	} 
+	else if(mid == start || mid == end) 
+	{	cout<<"\nElement not found";
+     		return;
+   	} 	
+	else if(item > a[mid])
+         	FibonacciSearch(a, mid, end, fib, index-1, item);
+      	else
+         	FibonacciSearch(a, start, mid, fib, index-2, item);
+}
+
+void main() 
+{	int n, i, fib[20], a[10]={3, 7, 55, 86, 7, 15, 26, 30, 46, 95};
+      	char ch;
+      	fib[0] = 0;
+      	fib[1] = 1;
+      	i = 1;
+      	while(fib[i] < 10) 
+	{	i++;
+         	fib[i] = fib[i-1] + fib[i-2];
+      	}
+     	up:
+         cout<<"\nEnter the Element to be searched: ";
+         cin>>n;
+         FibonacciSearch(a, 0, 9, fib, i, n);
+         cout<<"\n\n\tDo you want to search more...enter choice(y/n)?";
+         cin>>ch;
+
+	if(ch == 'y' || ch == 'Y')
+            goto up;
+
+	return 0;
+
+}