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Take list name from property name #379
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R/property.R
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if (is_property(x)) { | ||
x$name <- name | ||
if (is.null(x$name)) { |
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So an existing property $name
has priority over the name supplied in the list()
call if you supply both, right? I can't tell if that seems right or not, but don't have strong feelings either way
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Hmmm, I think the list name should win.
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That was also my gut feeling
Fixes #371