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/* | ||
Project Euler Problem 6 | ||
This turned out to be really easy | ||
Problem: | ||
The sum of the squares of the first ten natural numbers is, | ||
1**2 + 2**2 + ... + 10**2 = 385 | ||
The square of the sum of the first ten natural numbers is, | ||
(1 + 2 + ... + 10)**2 = 55**2 = 3025 | ||
Hence the difference between the sum of the squares of the first ten natural | ||
numbers and the square of the sum is 3025 − 385 = 2640. | ||
Find the difference between the sum of the squares of the first one hundred | ||
natural numbers and the square of the sum. | ||
*/ | ||
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pub fn p0006() -> u64 { | ||
let group = 1..101; | ||
let sum_of_squares = group.clone().fold(0, |x, y| x + y * y); | ||
let sum: u64 = group.sum(); | ||
let square_of_sum = sum * sum; | ||
return square_of_sum - sum_of_squares; | ||
} |