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/* | ||
Project Euler Problem 59 | ||
Problem: | ||
Each character on a computer is assigned a unique code and the preferred | ||
standard is ASCII (American Standard Code for Information Interchange). For | ||
example, uppercase A = 65, asterisk (*) = 42, and lowercase k = 107. | ||
A modern encryption method is to take a text file, convert the bytes to ASCII, | ||
then XOR each byte with a given value, taken from a secret key. The advantage | ||
with the XOR function is that using the same encryption key on the cipher text, | ||
restores the plain text; for example, 65 XOR 42 = 107, then 107 XOR 42 = 65. | ||
For unbreakable encryption, the key is the same length as the plain text | ||
message, and the key is made up of random bytes. The user would keep the | ||
encrypted message and the encryption key in different locations, and without | ||
both "halves", it is impossible to decrypt the message. | ||
Unfortunately, this method is impractical for most users, so the modified | ||
method is to use a password as a key. If the password is shorter than the | ||
message, which is likely, the key is repeated cyclically throughout the | ||
message. The balance for this method is using a sufficiently long password key | ||
for security, but short enough to be memorable. | ||
Your task has been made easy, as the encryption key consists of three lower | ||
case characters. Using cipher.txt (right click and 'Save Link/Target As...'), | ||
a file containing the encrypted ASCII codes, and the knowledge that the plain | ||
text must contain common English words, decrypt the message and find the sum of | ||
the ASCII values in the original text. | ||
*/ | ||
use itertools::Itertools; | ||
|
||
use crate::include::utils::{get_data_file,Answer}; | ||
|
||
pub fn p0059() -> Answer { | ||
let keyword = b"beginning"; | ||
let tokens = get_data_file("p0059_cipher.txt").split(',').map(|x| x.parse::<u8>().unwrap()).collect::<Vec<u8>>(); | ||
for key in b"abcdefghijklmnopqrtsuvwxyz".into_iter().permutations(3) { | ||
let plaintext = tokens.iter().enumerate().map(|(i, x)| *x ^ key[i % 3]).collect::<Vec<u8>>(); | ||
if plaintext.windows(keyword.len()).any(|w| w == keyword) { | ||
return Answer::Int(plaintext.into_iter().sum::<u64>()); | ||
} | ||
} | ||
return Answer::Int(-1); | ||
} |