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Co-authored-by: Edwin Fernando <[email protected]> Co-authored-by: AlexShefY <[email protected]>
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Submodule HumanEval-Dafny
updated
9 files
+11 −19 | 000-has_close_elements.dfy | |
+105 −44 | 001-separate-paren-groups.dfy | |
+1 −1 | 016-count_distinct_characters.dfy | |
+4 −4 | 025-factorize.dfy | |
+7 −7 | 037-sort_even.dfy | |
+1 −1 | 073-smallest_change.dfy | |
+5 −3 | 087-get_row.dfy | |
+3 −1 | 095-check_dict_case.dfy | |
+1 −1 | 105-by_length.dfy |
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The following errors occurred during verification: | ||
{error} | ||
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Please fix the error by adding, removing or modifying the invariants and/or assertions and return the fixed program. |
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There are still some errors: | ||
{error} | ||
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Could you please fix them? |
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prompts/humaneval-dafny-cot/rewrite/examples/001/answer.txt
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During the previous steps, we've found that the `sum_loop` function has a loop that goes over the elements of the array `numbers` and adds them to the `s` variable, which is equal to the `sum(numbers[..i])` for all `i`, such that `0 <= i <= |numbers|`. This means that during the execution of the loop the following invariant holds: | ||
1. `0 <= i <= |numbers|` | ||
2. `s == sum(numbers[..i])` | ||
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Let's put them in: | ||
```dafny | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
invariant 0 <= i <= |numbers| | ||
invariant s == sum(numbers[..i]) | ||
{ | ||
s := s + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` | ||
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We've also worked out how to prove the second invariant. For that we need to prove to the verifier that `sum(numbers[..i + 1]) == sum(numbers[..i]) + numbers[i]`. For that we need to use the `sum_prop` function, as follows: | ||
```dafny | ||
assert numbers[..i + 1][..i] == numbers[..i]; // assert that taking a slice of a slice is the same as taking a slice of the original array | ||
sum_prop(numbers[..i + 1]); // use a lemma to prove the invariant | ||
assert sum(numbers[..i + 1]) == sum(numbers[..i + 1][..i]) + numbers[i]; | ||
``` | ||
Let's add these lines to the code: | ||
```dafny | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
invariant 0 <= i <= |numbers| | ||
invariant s == sum(numbers[..i]) | ||
{ | ||
s := s + numbers[i]; | ||
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assert numbers[..i + 1][..i] == numbers[..i]; // assert that taking a slice of a slice is the same as taking a slice of the original array | ||
sum_prop(numbers[..i + 1]); // use a lemma to prove the invariant | ||
assert sum(numbers[..i + 1]) == sum(numbers[..i + 1][..i]) + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` | ||
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Other than that, we didn't find any other invariants or patterns that hold during the execution of the program. Therefore, the resulting program is (notice the lack of backticks): | ||
<answer> | ||
function sum(s: seq<int>) : int { | ||
if |s| == 0 then 0 else s[0] + sum(s[1..]) | ||
} | ||
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lemma sum_prop(s: seq<int>) | ||
requires |s| > 0 | ||
ensures sum(s) == sum(s[..|s| - 1]) + s[ |s| - 1 ] | ||
{ | ||
if (|s| > 1) { | ||
assert (s[1..][..|s[1..]| - 1]) == s[1..|s| - 1]; | ||
} | ||
} | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
invariant 0 <= i <= |numbers| | ||
invariant s == sum(numbers[..i]) | ||
{ | ||
s := s + numbers[i]; | ||
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assert numbers[..i + 1][..i] == numbers[..i]; // assert that taking a slice of a slice is the same as taking a slice of the original array | ||
sum_prop(numbers[..i + 1]); // use a lemma to prove the invariant | ||
assert sum(numbers[..i + 1]) == sum(numbers[..i + 1][..i]) + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
</answer> |
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prompts/humaneval-dafny-cot/rewrite/examples/001/question.txt
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It's time to rewrite the program to contain the invariants and assertions that we've found. Work on the following program and go step by step through the reasoning process. After that, output the rewritten program in the `<answer>` tag without backticks. | ||
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```dafny | ||
function sum(s: seq<int>) : int { | ||
if |s| == 0 then 0 else s[0] + sum(s[1..]) | ||
} | ||
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lemma sum_prop(s: seq<int>) | ||
requires |s| > 0 | ||
ensures sum(s) == sum(s[..|s| - 1]) + s[ |s| - 1 ] | ||
{ | ||
if (|s| > 1) { | ||
assert (s[1..][..|s[1..]| - 1]) == s[1..|s| - 1]; | ||
} | ||
} | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
{ | ||
s := s + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` |
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It's time to rewrite the program to contain the invariants and assertions that we've found. Work on the following program and go step by step through the reasoning process. After that, output the rewritten program in the `<answer>` tag without backticks. | ||
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{program} |
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prompts/humaneval-dafny-cot/steps/001/examples/001/answer.txt
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Let's go function by function. The first function, `sum` does not have a specification, as can be seen by the absence of either a `requires` or `ensures` clause. This means that this function is probably a specification itself. Let's consider, what it can be step by step. We can see that the aruguments to this function are a sequence of integers. We can see that the function returns an integer. We can conclude that the function does some accumulation of integers from the sequence. Looking at the body, we can see that the function takes the first element of the sequence and adds it to the accumulated result of evaluating the `sum` function on the rest of the sequence. This means the function is a specification for the sum of the elements of the sequence. | ||
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Next, we have the `sum_prop` lemma. Considering it's specification, we can see that it requires a non-empty sequence of integers, as seen by the `requires |s| > 0` clause. Looking at the ensures clause, we can see that the lemma ensures that the sum of the sequence (as computed by the `sum` function) is equal to the sum of the elements of the sequence without the last element, plus that last element. This is important to prove, because the sum function drops the first element and thus it is not obvious for the prover that the last element can be dropped in the same way. | ||
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Finally, we have the `sum_loop` method. This method has a specification, as indicated by the `ensures` clause. The specification states that the returned value `s` should be equal to the sum of the input sequence `numbers`, as computed by the `sum` function, as seen by the `ensures s == sum(numbers)` clause. | ||
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In summary: | ||
1. The `sum` function is itself a specification for computing the sum of a sequence of integers. | ||
2. The `sum_prop` lemma has a specification that proves a property about the `sum` function. | ||
3. The `sum_loop` method has a specification that ensures it correctly computes the sum of a sequence of integers, matching the result of the `sum` function. |
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prompts/humaneval-dafny-cot/steps/001/examples/001/question.txt
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Given the following program, for each function, determine if it has a specification. If it does not, is it itself a specification? If it is a specification, what does it specify? | ||
```dafny | ||
function sum(s: seq<int>) : int { | ||
if |s| == 0 then 0 else s[0] + sum(s[1..]) | ||
} | ||
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lemma sum_prop(s: seq<int>) | ||
requires |s| > 0 | ||
ensures sum(s) == sum(s[..|s| - 1]) + s[ |s| - 1 ] | ||
{ | ||
if (|s| > 1) { | ||
assert (s[1..][..|s[1..]| - 1]) == s[1..|s| - 1]; | ||
} | ||
} | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
{ | ||
s := s + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` |
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Given the following program, for each function, determine if it has a specification. If it does not, is it itself a specification? If it is a specification, what does it specify? | ||
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```dafny | ||
{program} | ||
``` |
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prompts/humaneval-dafny-cot/steps/002/examples/001/answer.txt
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Looking at the functions, we can see that the 'sum' function uses recursion and thus contains no loops. The 'sum_prop' lemma, in the same way, does not contain any loops, as evidenced by the absence of 'while' and 'for' keywords. | ||
Now, let's examine the 'sum_loop' method. This method contains a while loop that iterates through the elements of the 'numbers' sequence. The loop starts with 's' and 'i' initialized to 0, and continues as long as 'i' is less than the length of 'numbers'. Let's try to understand what 's' and 'i' represent in this context. | ||
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Looking at the body of the loop, we can see that it adds the current element of 'numbers' to 's'. This means that 's' is the running sum of the elements in 'numbers', namely 's = sum(numbers[..i])'. 'i' is easier to analyze. It is the index of the current element being processed. In each iteration of the loop, 'i' is incremented by 1, so 'i' represents the index of the next element to be processed. | ||
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Each iteration of the loop adds the current element to 's', and then increments 'i' to move to the next element. This process continues until 'i' reaches the length of 'numbers', at which point the loop terminates and 's' holds the final sum of the elements in 'numbers'. |
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prompts/humaneval-dafny-cot/steps/002/examples/001/question.txt
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Now we are finished with the specifications. Let's move onto the loops. | ||
Given the following program, for each function, determine if it has loops. If it does, try to determine what the loop does in detail. Go through all your thinking and reasoning process step by step. | ||
```dafny | ||
function sum(s: seq<int>) : int { | ||
if |s| == 0 then 0 else s[0] + sum(s[1..]) | ||
} | ||
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lemma sum_prop(s: seq<int>) | ||
requires |s| > 0 | ||
ensures sum(s) == sum(s[..|s| - 1]) + s[ |s| - 1 ] | ||
{ | ||
if (|s| > 1) { | ||
assert (s[1..][..|s[1..]| - 1]) == s[1..|s| - 1]; | ||
} | ||
} | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
{ | ||
s := s + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` |
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Given the following program, for each function, determine if it has loops. If it does, try to determine what the loop does in detail. Go through all your thinking and reasoning process step by step. | ||
```dafny | ||
{program} | ||
``` |
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prompts/humaneval-dafny-cot/steps/003/examples/001/answer.txt
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As we've seen, the loop in the `sum_loop` function goes over the elements of the array `numbers` and adds them to the `s` variable, which is equal to the `sum(numbers[..i])` for all `i`, such that `0 <= i <= |numbers|`. This means that during the execution of the loop the following invariant holds: | ||
1. `0 <= i <= |numbers|` | ||
2. `s == sum(numbers[..i])` | ||
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The second invariant might be a bit difficult to prove, as it adds the last element of the array to the sum, while, as I've said before, the `sum` function is defined as `sum(a) == a[0] + sum(a[1..])`. However, as we've seen, it's possible to use the `sum_prop` function to prove that this invariant holds. | ||
Let's work out how to use it. If applied to the `numbers[..i + 1]`, we get: | ||
`sum(numbers[..i + 1]) == sum(numbers[..i + 1][..i]) + numbers[i]`. It might be difficult for dafny to prove that `sum(numbers[..i + 1][..i]) == sum(numbers[..i])`, so I'd suggest adding an assertion before calling `sum_prop` to make sure that this is the case, namely `assert numbers[..i + 1][..i] == numbers[..i]`. | ||
So, to use the `sum_prop`, I'd suggest the following code: | ||
``` | ||
assert numbers[..i + 1][..i] == numbers[..i]; // assert that taking a slice of a slice is the same as taking a slice of the original array | ||
sum_prop(numbers[..i + 1]); // use a lemma to prove the invariant | ||
assert sum(numbers[..i + 1]) == sum(numbers[..i + 1][..i]) + numbers[i]; | ||
``` | ||
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In conclusion, we can say that two invariants hold and the second one could be proved using the `sum_prop` function. |
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prompts/humaneval-dafny-cot/steps/003/examples/001/question.txt
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As we've already analyzed the specifications and the loops, it's time to try to analyze what invariants and patterns hold during the execution of the program. Go over the found loops in the following program in the code and try to find out what invariants and patterns they hold. Go through all your thinking and reasoning process step by step. | ||
```dafny | ||
function sum(s: seq<int>) : int { | ||
if |s| == 0 then 0 else s[0] + sum(s[1..]) | ||
} | ||
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lemma sum_prop(s: seq<int>) | ||
requires |s| > 0 | ||
ensures sum(s) == sum(s[..|s| - 1]) + s[ |s| - 1 ] | ||
{ | ||
if (|s| > 1) { | ||
assert (s[1..][..|s[1..]| - 1]) == s[1..|s| - 1]; | ||
} | ||
} | ||
method sum_loop(numbers: seq<int>) returns (s: int) | ||
ensures s == sum(numbers) | ||
{ | ||
s := 0; | ||
var i := 0; | ||
while (i < |numbers|) | ||
{ | ||
s := s + numbers[i]; | ||
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i := i + 1; | ||
} | ||
} | ||
``` |
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As we've already analyzed the specifications and the loops, it's time to try to analyze what invariants and patterns hold during the execution of the program. Go over the found loops in the following program in the code and try to find out what invariants and patterns they hold. Go through all your thinking and reasoning process step by step. | ||
```dafny | ||
{program} | ||
``` |
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