[week-05-dp] 25215, 2533 #22
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wonkyDD
reviewed
Feb 21, 2024
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| for(int i=1; i<s.length(); ++i) { | ||
| if(s.charAt(i) >= 'a' && s.charAt(i) <= 'z') { // 소문자이면 | ||
| dp[0][i] = Math.min(dp[0][i-1] + 1, dp[1][i-1]+2); |
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오.. 각 문자열 인덱스마다 마름모 켜져있다/안켜져있다로 해서 2차원 dp를 돌리는군요
1149. RGB 거리 문제랑 거의 비슷하게 풀 수 있었네요 😊
wonkyDD
reviewed
Feb 21, 2024
| System.out.println(Math.min(dp[0][1], dp[1][1])); | ||
| } | ||
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| static void dfs(int cur, int prev) { |
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파라미터로 prev 를 전달하니까 외부에 방문했음을 나타내는 배열을 관리안해줘도 되는군요!
하나 알아갑니다 ;)
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close #17