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Day22 q2: Sum of Left Leaves SnowScriptWinterOfCode#464 cpp code adde…
…d by Akansha77
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/** | ||
* Definition for a binary tree node. | ||
* struct TreeNode { | ||
* int val; | ||
* TreeNode *left; | ||
* TreeNode *right; | ||
* TreeNode() : val(0), left(nullptr), right(nullptr) {} | ||
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} | ||
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} | ||
* }; | ||
*/ | ||
class Solution { | ||
void solve(TreeNode*root,int &sum,int &flag){ | ||
if(root==NULL)return ; | ||
if(root->left==NULL && root->right==NULL &&flag==1){ | ||
sum+=root->val; | ||
} | ||
flag=1; | ||
solve(root->left,sum,flag); | ||
flag=0; | ||
solve(root->right,sum,flag); | ||
|
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} | ||
public: | ||
int sumOfLeftLeaves(TreeNode* root) { | ||
int sum=0; | ||
int flag=0; | ||
solve(root,sum,flag); | ||
return sum; | ||
} | ||
}; |