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0104. Maximum Depth of Binary Tree.js
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0104. Maximum Depth of Binary Tree.js
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// Given a binary tree, find its maximum depth.
// The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
// Note: A leaf is a node with no children.
// Example:
// Given binary tree [3,9,20,null,null,15,7],
// 3
// / \
// 9 20
// / \
// 15 7
// return its depth = 3.
// 1) 递归 DFS
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
const maxDepth = (root) => {
if (!root) {
return 0
}
return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1
}
// Runtime: 60 ms, faster than 79.72% of JavaScript online submissions for Maximum Depth of Binary Tree.
// Memory Usage: 37.3 MB, less than 12.50% of JavaScript online submissions for Maximum Depth of Binary Tree.
// 2) BFS
// 思路:层层遍历,每经过一层遍历,最大深度 +1
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
const maxDepth = (root) => {
if (!root) {
return 0
}
let queue = [root]
let max = 0
while (queue.length) {
max++
let n = queue.length
for (let i = 0; i < n; i++) {
let node = queue.shift()
node.left && queue.push(node.left)
node.right && queue.push(node.right)
}
}
return max
}
// Runtime: 60 ms, faster than 79.72% of JavaScript online submissions for Maximum Depth of Binary Tree.
// Memory Usage: 37.1 MB, less than 62.50% of JavaScript online submissions for Maximum Depth of Binary Tree.
// Test case:
// let root = {
// val: 1,
// left: {
// val: 2,
// left: {
// val: 4,
// left: null,
// right: null
// },
// right: null
// },
// right: {
// val: 3,
// left: null,
// right: {
// val: 5,
// left: null,
// right: null
// }
// }
// }
// console.log(maxDepth(root))