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155.最小栈.rs
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155.最小栈.rs
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/*
* @lc app=leetcode.cn id=155 lang=rust
*
* [155] 最小栈
*
* https://leetcode-cn.com/problems/min-stack/description/
*
* algorithms
* Easy (57.37%)
* Likes: 1055
* Dislikes: 0
* Total Accepted: 295.5K
* Total Submissions: 514.9K
* Testcase Example: '["MinStack","push","push","push","getMin","pop","top","getMin"]\n' +
'[[],[-2],[0],[-3],[],[],[],[]]'
*
* 设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。
*
*
* push(x) —— 将元素 x 推入栈中。
* pop() —— 删除栈顶的元素。
* top() —— 获取栈顶元素。
* getMin() —— 检索栈中的最小元素。
*
*
*
*
* 示例:
*
* 输入:
* ["MinStack","push","push","push","getMin","pop","top","getMin"]
* [[],[-2],[0],[-3],[],[],[],[]]
*
* 输出:
* [null,null,null,null,-3,null,0,-2]
*
* 解释:
* MinStack minStack = new MinStack();
* minStack.push(-2);
* minStack.push(0);
* minStack.push(-3);
* minStack.getMin(); --> 返回 -3.
* minStack.pop();
* minStack.top(); --> 返回 0.
* minStack.getMin(); --> 返回 -2.
*
*
*
*
* 提示:
*
*
* pop、top 和 getMin 操作总是在 非空栈 上调用。
*
*
*/
// @lc code=start
struct MinStack {
stack: Vec<i32>,
min_stack: Vec<i32>,
}
/**
* `&self` means the method takes an immutable reference.
* If you need a mutable reference, change it to `&mut self` instead.
*/
impl MinStack {
fn new() -> Self {
MinStack {
stack: Vec::new(),
min_stack: Vec::new(),
}
}
fn push(&mut self, val: i32) {
self.stack.push(val);
if self.min_stack.is_empty() || val <= *self.min_stack.last().unwrap() {
self.min_stack.push(val);
}
}
fn pop(&mut self) {
if self.min_stack.is_empty() {
return;
}
if self.stack.pop().unwrap() == *self.min_stack.last().unwrap() {
self.min_stack.pop();
}
}
fn top(&self) -> i32 {
return *self.stack.last().unwrap();
}
fn get_min(&self) -> i32 {
return *self.min_stack.last().unwrap();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* let obj = MinStack::new();
* obj.push(val);
* obj.pop();
* let ret_3: i32 = obj.top();
* let ret_4: i32 = obj.get_min();
*/
// @lc code=end