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UVC dose to inactivate SARS-COV-19 #8
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The estimations in the video arrive at a radiation energy of 1,325mJ/cm^2 in the middle of the pipe, which is several orders of magnitude more then what seems to be required for 90% inactivation. |
Given that more then 90% of UVC gets reflected by the mirror sheeting in the pipe and thus the radiation intensity is higher and UVC dose for 90% inactivation of SARS-COV-19 virus is three times lower then assumed in the video, the effectiveness is most likely significantly better then 60% (as calculated in the video). |
better source for k value for sars-cov-19: https://pubmed.ncbi.nlm.nih.gov/32547908/ it quotes the 90% UVC dose to be 10,3mJ/cm^2. Edit: it appears tht the value of 10.3mJ/cm^2 is not for 90% inactivation but for 99%. see comments below. |
https://www.tandfonline.com/doi/full/10.1080/02786820500428575 this is a paper from 2005, on inactivating germs with UVC, and gives a broader scientific overview. It says
Sars-CoV-19 is ssRNA, as I found in this paper
That means that the 90% UVC dose quoted in the scientific paper is most likely meant to be a 99.9% dose. Looking at this paper https://www.nature.com/articles/s41598-020-67211-2.pdf
the 90% dose is given here:
Conveniently, this also gives the k-factor for both corona virus types of 4.1cm^2/mJ and 5.9cm^2/mJ. |
https://www.uvdi.com/international/wp-content/uploads/2020/03/International-News-Release-Med-Mar2020_MKTFM-454-Rev-A.pdf
on page 3 it quotes a dose of 611 uJ/cm^2 for 90% inactivation of sars-cov-19. Influenza-A is ~3 times as high at 1935uJ/cm^2.
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