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box_utils.py
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box_utils.py
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#!/usr/bin/env python
# -*- coding: UTF-8 -*-
"""
This script implements algorithm for finding intersecting rectangles,
both on the 2D dotplot and 1D-projection, both routines are used by quota_align.py
"""
from grouper import Grouper
def range_overlap(a, b):
"""
>>> range_overlap(("1", 30, 45), ("1", 45, 55))
True
>>> range_overlap(("1", 30, 45), ("1", 57, 68))
False
>>> range_overlap(("1", 30, 45), ("2", 42, 55))
False
"""
a_chr, a_min, a_max = a
b_chr, b_min, b_max = b
# must be on the same chromosome
if a_chr!=b_chr: return False
return (a_min <= b_max) and (b_min <= a_max)
def get_1D_overlap(eclusters, depth=1):
"""
Find blocks that are 1D overlapping,
returns cliques of block ids that are in conflict
"""
overlap_set = set()
active = set()
ends = []
for i, (chr, left, right) in enumerate(eclusters):
ends.append((chr, left, 0, i)) # 0/1 for left/right-ness
ends.append((chr, right, 1, i))
ends.sort()
chr_last = ""
for chr, pos, left_right, i in ends:
if chr != chr_last: active.clear()
if left_right==0: active.add(i)
else: active.remove(i)
if len(active) > depth:
overlap_set.add(tuple(sorted(active)))
chr_last = chr
return overlap_set
def get_2D_overlap(chain, eclusters):
"""
Implements a sweep line algorithm, that has better running time than naive O(n^2):
assume block has x_ends, and y_ends for the bounds
1. sort x_ends, and take a sweep line to scan the x_ends
2. if left end, test y-axis intersection of current block with `active` set;
also put this block in the `active` set
3. if right end, remove block from the `active` set
"""
mergeables = Grouper()
active = set()
x_ends = []
for i, (range_x, range_y, score) in enumerate(eclusters):
chr, left, right = range_x
x_ends.append((chr, left, 0, i)) # 0/1 for left/right-ness
x_ends.append((chr, right, 1, i))
x_ends.sort()
chr_last = ""
for chr, pos, left_right, i in x_ends:
if chr != chr_last: active.clear()
if left_right==0:
active.add(i)
for x in active:
# check y-overlap
if range_overlap(eclusters[x][1], eclusters[i][1]):
mergeables.join(x, i)
else: # right end
active.remove(i)
chr_last = chr
return mergeables
if __name__ == '__main__':
import doctest
doctest.testmod()