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50_Pow(x, n).py
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50_Pow(x, n).py
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'''
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10
Output: 1024.00000
Example 2:
Input: 2.10000, 3
Output: 9.26100
Example 3:
Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Note:
-100.0 < x < 100.0
n is a 32-bit signed integer, within the range [−231, 231 − 1]
'''
class Solution(object):
def myPow(self, x, n):
"""
:type x: float
:type n: int
:rtype: float
"""
def DFS(x, n):
if n == 0: return 1 # n**0 = 1
half = DFS(x, n//2) # exp: 2**100 = 2**50 * 2**50
if n%2 == 0:
return half*half
else:
return half*half*x # exp: 2**101 = 2**50 * 2**50 * 2
if n < 0:
return 1/DFS(x, -n) # n is a negative num
else:
return DFS(x, n)