sql-solutions.md

layout	root	title
lesson	.	Solutions to SQL exercises

WARNING

This file may not be always up to date with regards to the exact exercises instructions and the naming of the columns and tables in the database. Check before you run the workshop!

EXERCISE

Write a query that returns the year, month, day, species ID and weight (in mg).

SOLUTION

SELECT day, month, year, species_id, weight * 1000
FROM surveys;

EXERCISE

Write a query that returns the day, month, year, species ID, and weight (in kg) for individuals caught on Plot 1 that weigh more than 75 g.

SOLUTION

SELECT day, month, year, species_id, weight / 1000
FROM surveys
WHERE plot_id = 1
AND weight > 75;

EXERCISE

Write a query that returns the day, month, year, species ID, and weight (in kg) for individuals caught on Plot 1 that weigh more than 75 g.

SOLUTION

SELECT
	surveys.day,
	surveys.month,
	surveys.year,
	species.species_id,
	surveys.weight / 1000
FROM surveys
JOIN species ON surveys.species_id = species.species_id
WHERE surveys.weight > 75
AND surveys.plot_id = 1;

EXERCISE

Write a query that returns day, month, year, species ID for individuals caught in January, May and July.

SOLUTION

SELECT day, month, year, species_id
FROM surveys
WHERE month IN (1, 5, 7);

EXERCISE

Write a query that returns year, species ID, and weight in kg from the surveys table, sorted with the largest weights at the top.

SOLUTION

SELECT year, species_id, weight / 1000
FROM surveys ORDER BY weight DESC;

EXERCISE

Let’s try to combine what we’ve learned so far in a single query. Using the surveys table write a query to display the three date fields, species ID, and weight in kilograms (rounded to two decimal places), for rodents captured in 1999, ordered alphabetically by the species ID.

SOLUTION

SELECT year, month, day, species_id, ROUND(weight / 1000, 2)
FROM surveys
WHERE year = 1999
ORDER BY species_id;

EXERCISE

Write queries that return:

1. How many individuals were counted in each year.

2. Average weight of each species in each year.

SOLUTION

SELECT year, COUNT(*)
FROM surveys
GROUP BY year;

SELECT year, species_id, ROUND(AVG(weight), 2)
FROM surveys
GROUP BY year, species_id;

EXERCISE

Write a query that returns the number of each species caught in each year sorted from most often caught species to the least occurring ones within each year starting from the most recent records.

SOLUTION

SELECT year, species_id, COUNT(*)
FROM surveys
GROUP BY year, species_id
ORDER BY year DESC, COUNT(*) DESC;

EXERCISE

Write a query that returns the genus, the species, and the weight of every individual captured at the site.

SOLUTION

SELECT species.genus, species.species_id, surveys.weight
FROM surveys
JOIN species ON surveys.species_id = species.species_id;

EXERCISE

Write a query that returns the number of genus of the animals caught in each plot in descending order.

SOLUTION

SELECT surveys.plot_id, species.genus, COUNT(*)
FROM surveys
JOIN species ON surveys.species_id = species.species_id
GROUP BY species.genus, surveys.plot_id
ORDER BY surveys.plot_id, COUNT(*) DESC