1773. Count Items Matching a Rule.py

'''Did this late night'''
class Solution:
    def countMatches(self, items: List[List[str]], ruleKey: str, ruleValue: str) -> int:
        ctr = 0
        for i in items:
            if ruleKey == 'type':
                if i[0] == ruleValue:
                    ctr +=1
            if ruleKey == 'color':
                if i[1] == ruleValue:
                    ctr +=1
            if ruleKey == 'name':
                if i[2] == ruleValue:
                    ctr +=1

        return ctr

      
'''
You are given an array items, where each items[i] = [typei, colori, namei] describes the type, color, and name of the ith item. You are also given a rule represented by two strings, ruleKey and ruleValue.

The ith item is said to match the rule if one of the following is true:

ruleKey == "type" and ruleValue == typei.
ruleKey == "color" and ruleValue == colori.
ruleKey == "name" and ruleValue == namei.
Return the number of items that match the given rule.

 

Example 1:

Input: items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
Output: 1
Explanation: There is only one item matching the given rule, which is ["computer","silver","lenovo"].
Example 2:

Input: items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
Output: 2
Explanation: There are only two items matching the given rule, which are ["phone","blue","pixel"] and ["phone","gold","iphone"]. Note that the item ["computer","silver","phone"] does not match.
 

Constraints:

1 <= items.length <= 104
1 <= typei.length, colori.length, namei.length, ruleValue.length <= 10
ruleKey is equal to either "type", "color", or "name".
All strings consist only of lowercase letters.
'''