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Create a zip file from the MemoryStream: using System;
using System.IO;
using System.IO.Compression;
using System.Net.Mail;
// Assuming you have a MemoryStream called "logFileStream"
// Step 1: Create a zip file from the MemoryStream
using (MemoryStream zipMemoryStream = new MemoryStream())
{
using (ZipArchive zipArchive = new ZipArchive(zipMemoryStream, ZipArchiveMode.Create, true))
{
// Create a new entry in the zip file
ZipArchiveEntry entry = zipArchive.CreateEntry("logFile.txt");
// Write the MemoryStream data into the zip entry
using (Stream entryStream = entry.Open())
{
logFileStream.CopyTo(entryStream);
}
}
// Step 2: Send the zip file as an email attachment
using (SmtpClient smtpClient = new SmtpClient("your_SMTP_server"))
{
MailMessage mailMessage = new MailMessage();
mailMessage.From = new MailAddress("[email protected]");
mailMessage.To.Add("[email protected]");
mailMessage.Subject = "Log Files";
mailMessage.Body = "Please find attached log files.";
mailMessage.Attachments.Add(new Attachment(zipMemoryStream, "logFiles.zip"));
smtpClient.Send(mailMessage);
}
} |
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So if I use the ILogCompressor to get the log files back as a MemoryStream, how do I convert the MemoryStream to an actual zip file that I can attach to an email and send back to me from the user?
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