-
Notifications
You must be signed in to change notification settings - Fork 9
/
day17.rs
52 lines (44 loc) · 1.39 KB
/
day17.rs
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
//! # Spinlock
//!
//! There are two insights that speed up part two.
//!
//! The first is that we don't need a buffer. We only need to preserve the last value inserted
//! whenever the index becomes zero. Once 50 million values have been inserted then this value
//! is the final result.
//!
//! The second trick is realizing that we can insert multiple values at a time before the index
//! wraps around. For example if the index is 1, the current value 10,000 and the step 300,
//! then we can insert 34 values at once. The [`div_ceil`] method is perfect for this computation.
//!
//! This reduces the number of loops needed to approximately √50000000 = 7071.
//!
//! [`div_ceil`]: usize::div_ceil
use crate::util::parse::*;
pub fn parse(input: &str) -> usize {
input.unsigned()
}
pub fn part1(input: &usize) -> u16 {
let step = input + 1;
let mut index = 0;
let mut buffer = vec![0];
for n in 0..2017 {
index = (index + step) % buffer.len();
buffer.insert(index, n + 1);
}
buffer[(index + 1) % buffer.len()]
}
pub fn part2(input: &usize) -> usize {
let step = input + 1;
let mut n: usize = 1;
let mut index = 0;
let mut result = 0;
while n <= 50_000_000 {
if index == 0 {
result = n;
}
let skip = (n - index).div_ceil(step);
n += skip;
index = (index + skip * step) % n;
}
result
}