Due by 11:59pm on Wednesday, March 13.
Starter Files
Download lab07.zip. Inside the archive, you will find starter files for the questions in this lab, along with a copy of the Ok autograder.
Required Questions
Getting Started Videos
These videos may provide some helpful direction for tackling the coding problems on this assignment.
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Inheritance
Consult the drop-down if you need a refresher on Inheritance. It's okay to skip directly to the questions and refer back here should you get stuck.
To avoid redefining attributes and methods for similar classes, we can write a single base class from which more specialized classes inherit. For example, we can write a class called Pet
and define Dog
as a subclass of Pet
:
class Pet: def __init__(self, name, owner): self.is_alive = True # It's alive!!! self.name = name self.owner = owner def eat(self, thing): print(self.name + " ate a " + str(thing) + "!") def talk(self): print(self.name)class Dog(Pet): def talk(self): super().talk() print('This Dog says woof!')
Inheritance represents a hierarchical relationship between two or more classes where one class is a more specific version of the other: a dog is a pet (We use is a to describe this sort of relationship in OOP languages, and not to refer to the Python is
operator).
Since Dog
inherits from Pet
, the Dog
class will also inherit the Pet
class's methods, so we don't have to redefine __init__
or eat
. We do want each Dog
to talk
in a Dog
-specific way, so we can override the talk
method.
We can use super()
to refer to the superclass of self
, and access any superclass methods as if we were an instance of the superclass. For example, super().talk()
in the Dog
class will call the talk
method from the Pet
class, but passing the Dog
instance as the self
.
Q1: WWPD: Inheritance ABCs
Important: For all WWPD questions, type
Function
if you believe the answer is<function...>
,Error
if it errors, andNothing
if nothing is displayed.Use Ok to test your knowledge with the following "What Would Python Display?" questions:
python3 ok -q inheritance-abc -u
>>> class A:... x, y = 0, 0... def __init__(self):... return>>> class B(A):... def __init__(self):... return>>> class C(A):... def __init__(self):... return>>> print(A.x, B.x, C.x)____________>>> B.x = 2>>> print(A.x, B.x, C.x)____________>>> A.x += 1>>> print(A.x, B.x, C.x)____________>>> obj = C()>>> obj.y = 1>>> C.y == obj.y____________>>> A.y = obj.y>>> print(A.y, B.y, C.y, obj.y)____________
Class Practice
Let's say we'd like to model a bank account that can handle interactions such as depositing funds or gaining interest on current funds. In the following questions, we will be building off of the Account
class. Here's our current definition of the class:
class Account: """An account has a balance and a holder. >>> a = Account('John') >>> a.deposit(10) 10 >>> a.balance 10 >>> a.interest 0.02 >>> a.time_to_retire(10.25) # 10 -> 10.2 -> 10.404 2 >>> a.balance # Calling time_to_retire method should not change the balance 10 >>> a.time_to_retire(11) # 10 -> 10.2 -> ... -> 11.040808032 5 >>> a.time_to_retire(100) 117 """ max_withdrawal = 10 interest = 0.02 def __init__(self, account_holder): self.balance = 0 self.holder = account_holder def deposit(self, amount): self.balance = self.balance + amount return self.balance def withdraw(self, amount): if amount > self.balance: return "Insufficient funds" if amount > self.max_withdrawal: return "Can't withdraw that amount" self.balance = self.balance - amount return self.balance
Q2: Retirement
Add a time_to_retire
method to the Account
class. This method takes in an amount
and returns how many years the holder would need to wait in order for the current balance
to grow to at least amount
, assuming that the bank adds the interest (calculated as the current balance
multiplied by the interest
rate) to the balance
at the end of each year.
```def time_to_retire(self, amount): """Return the number of years until balance would grow to amount.""" assert self.balance > 0 and amount > 0 and self.interest > 0 "*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q Account
### Q3: FreeCheckingImplement the `FreeChecking` class, which is like the `Account` class from lecture except that it charges a withdraw fee `withdraw_fee` after withdrawing `free_withdrawals` number of times. If a withdrawal is unsuccessful, it still counts towards the number of free withdrawals remaining, but no fee for the withdrawal will be charged.
class FreeChecking(Account): """A bank account that charges for withdrawals, but the first two are free!
>>> ch = FreeChecking('Jack')>>> ch.balance = 20>>> ch.withdraw(100) # First one's free. Still counts as a free withdrawal even though it was unsuccessful'Insufficient funds'>>> ch.withdraw(3) # Second withdrawal is also free17>>> ch.balance17>>> ch.withdraw(3) # Ok, two free withdrawals is enough, as free_withdrawals is only 213>>> ch.withdraw(3)9>>> ch2 = FreeChecking('John')>>> ch2.balance = 10>>> ch2.withdraw(3) # No fee7>>> ch.withdraw(3) # ch still charges a fee5>>> ch.withdraw(5) # Not enough to cover fee + withdraw'Insufficient funds'"""withdraw_fee = 1free_withdrawals = 2"*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q FreeChecking
## Linked ListsConsult the drop-down if you need a refresher on Linked Lists. It's okay to skip directly to the questions and refer back here should you get stuck.A linked list is a data structure for storing a sequence of values. It is more efficient than a regular built-in list for certain operations, such as inserting a value in the middle of a long list. Linked lists are not built in, and so we define a class called `Link` to represent them. A linked list is either a `Link` instance or `Link.empty` (which represents an empty linked list).A instance of `Link` has two instance attributes, `first` and `rest`.
class Link: """A linked list.
>>> s = Link(1)>>> s.first1>>> s.rest is Link.emptyTrue>>> s = Link(2, Link(3, Link(4)))>>> s.first = 5>>> s.rest.first = 6>>> s.rest.rest = Link.empty>>> s # Displays the contents of repr(s)Link(5, Link(6))>>> s.rest = Link(7, Link(Link(8, Link(9))))>>> sLink(5, Link(7, Link(Link(8, Link(9)))))>>> print(s) # Prints str(s)<5 7 <8 9>>"""empty = ()def __init__(self, first, rest=empty): assert rest is Link.empty or isinstance(rest, Link) self.first = first self.rest = restdef __repr__(self): if self.rest is not Link.empty: rest_repr = ', ' + repr(self.rest) else: rest_repr = '' return 'Link(' + repr(self.first) + rest_repr + ')'def __str__(self): string = '<' while self.rest is not Link.empty: string += str(self.first) + ' ' self = self.rest return string + str(self.first) + '>'
The `rest` attribute of a `Link` instance should always be a linked list: either another `Link` instance or `Link.empty`. It SHOULD NEVER be `None`.To check if a linked list is empty, compare it to `Link.empty`. Since there is only ever one empty list, we can use `is` to compare, but `==` would work too.
def is_empty(s): """Return whether linked list s is empty.""" return s is Link.empty:
### Q4: WWPD: Linked ListsRead over the `Link` class. Make sure you understand the doctests.> Use Ok to test your knowledge with the following "What Would Python Display?" questions:> > ```> python3 ok -q link -u> ```> > Enter `Function` if you believe the answer is `<function ...>`, `Error` if it errors, and `Nothing` if nothing is displayed.> > If you get stuck, try drawing out the box-and-pointer diagram for the linked list on a piece of paper or loading the `Link` class into the interpreter with `python3 -i lab08.py`.
link = Link(1000) link.first **__**1000 link.rest is Link.empty **__**True link = Link(1000, 2000) **__**AssertionError link = Link(1000, Link()) **__**TypeError
>>> link = Link(1, Link(2, Link(3)))>>> link.first______1>>> link.rest.first______2>>> link.rest.rest.rest is Link.empty______True>>> link.first = 9001>>> link.first______9001>>> link.rest = link.rest.rest>>> link.rest.first______3>>> link = Link(1)>>> link.rest = link>>> link.rest.rest is Link.empty______False>>> link.rest.rest.rest.rest.first______1>>> link = Link(2, Link(3, Link(4)))>>> link2 = Link(1, link)>>> link2.first______1>>> link2.rest.first______2
>>> link = Link(5, Link(6, Link(7)))>>> link # Look at the __repr__ method of Link______Link(5, Link(6, Link(7)))>>> print(link) # Look at the __str__ method of Link______<5 6 7>
Q5: Duplicate Link
Write a function duplicate_link
that takes in a linked list s
and a value val
. It mutates s
so that each element equal to val
is followed by an additional val
(a duplicate copy). It returns None
.
Note: In order to insert a link into a linked list, reassign the
rest
attribute of theLink
instances that haveval
as theirfirst
. Try drawing out a doctest to visualize!
def duplicate_link(s, val): """Mutates s so that each element equal to val is followed by another val. >>> x = Link(5, Link(4, Link(5))) >>> duplicate_link(x, 5) >>> x Link(5, Link(5, Link(4, Link(5, Link(5))))) >>> y = Link(2, Link(4, Link(6, Link(8)))) >>> duplicate_link(y, 10) >>> y Link(2, Link(4, Link(6, Link(8)))) >>> z = Link(1, Link(2, (Link(2, Link(3))))) >>> duplicate_link(z, 2) # ensures that back to back links with val are both duplicated >>> z Link(1, Link(2, Link(2, Link(2, Link(2, Link(3)))))) """ "*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q duplicate_link
Check Your Score Locally
You can locally check your score on each question of this assignment by running
python3 ok --score
This does NOT submit the assignment! When you are satisfied with your score, submit the assignment to Gradescope to receive credit for it.
Submit
Submit this assignment by uploading any files you've edited to the appropriate Gradescope assignment. Lab 00 has detailed instructions.
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