Given preorder and inorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
preorder = [3,9,20,15,7] inorder = [9,3,15,20,7]
Return the following binary tree:
3 / \ 9 20 / \ 15 7
Given preorder and inorder traversal of a tree, construct the binary tree.
Note:
You may assume that duplicates do not exist in the tree.
preorder = [3,9,20,15,7] inorder = [9,3,15,20,7]
Return the following binary tree:
3 / \ 9 20 / \ 15 7