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伪代码第一个if判prev == root->parent成立后
缺少prev=root;
当然给出的示例implementation是不缺少的
The text was updated successfully, but these errors were encountered:
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伪代码第一个if判prev == root->parent成立后
缺少prev=root;
当然给出的示例implementation是不缺少的
The text was updated successfully, but these errors were encountered: