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_78.java
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_78.java
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package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.List;
/**
* 78. Subsets
*
* Given a set of distinct integers, nums, return all possible subsets.
* Note: The solution set must not contain duplicate subsets.
For example,
If nums = [1,2,3], a solution is:
[
[3],
[1],
[2],
[1,2,3],
[1,3],
[2,3],
[1,2],
[]
]
*/
public class _78 {
public static class Solution1 {
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> result = new ArrayList();
if (nums == null) {
return result;
}
result.add(new ArrayList());
for (int i = 0; i < nums.length; i++) {
List<List<Integer>> temp = new ArrayList();
//you'll have to create a new one here, otherwise, it'll throw ConcurrentModificationException.
for (List<Integer> list : result) {
List<Integer> newList = new ArrayList(list);
newList.add(nums[i]);
temp.add(newList);
}
result.addAll(temp);
}
return result;
}
}
public static class Solution2 {
/**This is the most straightforward solution and easy to follow.*/
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> result = new ArrayList();
backtracking(result, new ArrayList(), nums, 0);
return result;
}
void backtracking(List<List<Integer>> result, List<Integer> list, int[] nums, int start) {
result.add(new ArrayList(list));
for (int i = start; i < nums.length; i++) {
list.add(nums[i]);
backtracking(result, list, nums, i + 1);
list.remove(list.size() - 1);
}
}
}
public static class Solution3 {
/**
* This is just a slight modification of Solution2, pay close to attention to notice the difference between them.
*/
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> result = new ArrayList<>();
List<Integer> list = new ArrayList<>();
result.add(list);
backtracking(result, list, nums, 0);
return result;
}
private void backtracking(List<List<Integer>> result, List<Integer> list, int[] nums, int start) {
for (int i = start; i < nums.length; i++) {
list.add(nums[i]);
result.add(new ArrayList<>(list));
backtracking(result, list, nums, i + 1);
list.remove(list.size() - 1);
}
}
}
}