-
Notifications
You must be signed in to change notification settings - Fork 26
/
429.N-aryTreeLevelOrderTraversal.py
46 lines (41 loc) · 1.6 KB
/
429.N-aryTreeLevelOrderTraversal.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
"""
Given an n-ary tree, return the level order traversal of its nodes' values.
Nary-Tree input serialization is represented in their level order traversal,
each group of children is separated by the null value (See examples).
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
Constraints:
- The height of the n-ary tree is less than or equal to 1000
- The total number of nodes is between [0, 10^4]
"""
#Difficulty: Medium
#37 / 37 test cases passed.
#Runtime: 48 ms
#Memory Usage: 15.6 MB
#Runtime: 48 ms, faster than 94.40% of Python3 online submissions for N-ary Tree Level Order Traversal.
#Memory Usage: 15.6 MB, less than 67.55% of Python3 online submissions for N-ary Tree Level Order Traversal.
"""
# Definition for a Node.
class Node:
def __init__(self, val=None, children=None):
self.val = val
self.children = children
"""
class Solution:
def levelOrder(self, root: 'Node') -> List[List[int]]:
if not root: return None
depth = 0
queue = {depth : [root]}
while queue:
if depth > len(queue)-1:
break
level = queue[depth]
for i in range(len(level)):
if level[i].children:
if depth+1 in queue:
queue[depth+1] += level[i].children
else:
queue[depth+1] = level[i].children
level[i] = level[i].val
depth += 1
return queue.values()