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1409.QueriesonaPermutationWithKey.py
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1409.QueriesonaPermutationWithKey.py
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'''
Given the array queries of positive integers between 1
and m, you have to process all queries[i] (from i=0 to
i=queries.length-1) according to the following rules:
- In the beginning, you have the permutation
P=[1,2,3,...,m].
- For the current i, find the position of queries[i]
in the permutation P (indexing from 0) and then move
this at the beginning of the permutation P. Notice
that the position of queries[i] in P is the result
for queries[i].
Return an array containing the result for the given queries.
Example:
Input: queries = [3,1,2,1], m = 5
Output: [2,1,2,1]
Explanation: The queries are processed as follow:
- For i=0: queries[i]=3, P=[1,2,3,4,5],
position of 3 in P is 2, then we move 3
to the beginning of P resulting in
P=[3,1,2,4,5].
- For i=1: queries[i]=1, P=[3,1,2,4,5],
position of 1 in P is 1, then we move 1
to the beginning of P resulting in
P=[1,3,2,4,5].
- For i=2: queries[i]=2, P=[1,3,2,4,5],
position of 2 in P is 2, then we move 2
to the beginning of P resulting in
P=[2,1,3,4,5].
- For i=3: queries[i]=1, P=[2,1,3,4,5],
position of 1 in P is 1, then we move 1
to the beginning of P resulting in
P=[1,2,3,4,5].
- Therefore, the array containing the result
is [2,1,2,1].
Example:
Input: queries = [4,1,2,2], m = 4
Output: [3,1,2,0]
Example:
Input: queries = [7,5,5,8,3], m = 8
Output: [6,5,0,7,5]
Constraints:
- 1 <= m <= 10^3
- 1 <= queries.length <= m
- 1 <= queries[i] <= m
'''
#Difficulty: Medium
#53 / 53 test cases passed.
#Runtime: 48 ms
#Memory Usage: 14.6 MB
#Runtime: 48 ms, faster than 97.70% of Python3 online submissions for Queries on a Permutation With Key.
#Memory Usage: 14.6 MB, less than 11.49% of Python3 online submissions for Queries on a Permutation With Key.
class Solution:
def processQueries(self, queries: List[int], m: int) -> List[int]:
permutation = [n for n in range(1, m+1)]
for i, n in enumerate(queries):
queries[i] = permutation.index(n)
permutation.insert(0, permutation.pop(queries[i]))
return queries