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1463.CherryPickupII.py
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1463.CherryPickupII.py
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'''
Given a rows x cols matrix grid representing a field of
cherries. Each cell in grid represents the number of
cherries that you can collect.
You have two robots that can collect cherries for you,
Robot #1 is located at the top-left corner (0,0) , and
Robot #2 is located at the top-right corner (0, cols-1)
of the grid.
Return the maximum number of cherries collection using
both robots by following the rules below:
- From a cell (i,j), robots can move to cell
(i+1, j-1), (i+1, j) or (i+1, j+1).
- When any robot is passing through a cell, It picks
it up all cherries, and the cell becomes an empty
cell (0).
- When both robots stay on the same cell, only one
of them takes the cherries.
- Both robots cannot move outside of the grid at any
moment.
- Both robots should reach the bottom row in the grid.
Example:
Input: grid = [[3,1,1],
[2,5,1],
[1,5,5],
[2,1,1]]
Output: 24
Explanation: Path of robot #1 and #2 are described in
color green and blue respectively.
Cherries taken by Robot #1, (3 + 2 + 5 + 2)
= 12.
Cherries taken by Robot #2, (1 + 5 + 5 + 1)
= 12.
Total of cherries: 12 + 12 = 24.
Example:
Input: grid = [[1,0,0,0,0,0,1],
[2,0,0,0,0,3,0],
[2,0,9,0,0,0,0],
[0,3,0,5,4,0,0],
[1,0,2,3,0,0,6]]
Output: 28
Explanation: Path of robot #1 and #2 are described in
color green and blue respectively.
Cherries taken by Robot #1, (1 + 9 + 5 + 2)
= 17.
Cherries taken by Robot #2, (1 + 3 + 4 + 3)
= 11.
Total of cherries: 17 + 11 = 28.
Example:
Input: grid = [[1,0,0,3],[0,0,0,3],[0,0,3,3],[9,0,3,3]]
Output: 22
Example:
Input: grid = [[1,1],[1,1]]
Output: 4
Constraints:
- rows == grid.length
- cols == grid[i].length
- 2 <= rows, cols <= 70
- 0 <= grid[i][j] <= 100
'''
#Difficulty: Hard
#58 / 58 test cases passed.
#Runtime: 1024 ms
#Memory Usage: 54.6 MB
#Runtime: 1024 ms, faster than 68.56% of Python3 online submissions for Cherry Pickup II.
#Memory Usage: 54.6 MB, less than 5.28% of Python3 online submissions for Cherry Pickup II.
class Solution:
def cherryPickup(self, grid: List[List[int]]) -> int:
self.grid = grid
self.rows = len(grid)
self.cols = len(grid[0])
return self.dfs(0, 0, self.cols-1)
@lru_cache(None)
def dfs(self, row, x, y):
if x < 0 or x >= self.cols or y < 0 or y >= self.cols:
return 0
result = 0
result += self.grid[row][x]
if x != y:
result += self.grid[row][y]
if row < self.rows - 1:
vals = []
for i in [x-1, x, x+1]:
for j in [y-1, y, y+1]:
vals.append(self.dfs(row+1, i, j))
result += max(vals)
return result