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Lesson 5 Step 4 #140
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All your answer is correct and equivalent. There is no better answer in your case. |
thanks.. |
I would assume the simple solution to be the following: let up = Char.uppercase in
let big_xy = List.map up xy in
let big_ab = List.map up ab in
big_ab @ big_xy |
Lesson 5 Step 4 introduces concepts not covered before the step.
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hi i newbie with ocaml..
I do this solutions.. but nothing say me that is it the answer:
val up : char list = ['A'; 'B'; 'X'; 'Y']
or
val up : char list = ['A'; 'B'; 'X'; 'Y']
or
val up : char list = ['A'; 'B'; 'X'; 'Y']
thanks..
for any answer.
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