Missing ical_uid after new outlook event .save

[aadslingerland]

Greetings,
A question about saving a new outlook event using MS Graph through O365.

After new_outlook_event.save various properties of the new_outlook_event object are updated. However my much needed ical_uid (to uniquelly identify an event) has no value.

How can I get the ical_uid value just after creating a new event? Did I miss something considering the .save method?

[alejcas]

Can you tell where this "ical_uid" is in the ms graph docs?

[aadslingerland]

ical_uid is one of the many properties of an outlook event [image: ical_uid_1.PNG] Here the value is None (just after creating a new event with outllok_event.save() [image: ical_uid_2.PNG] Here the value is the unique identifier of an event when reading it back See also: event resource type - Microsoft Graph v1.0 | Microsoft Learn <https://learn.microsoft.com/en-us/graph/api/resources/event?view=graph-rest-1.0> [image: image.png]

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On Mon, 28 Nov 2022 at 23:05, Alejandro Casanovas ***@***.***> wrote: Can you tell where this "ical_uid" is in the ms graph docs? — Reply to this email directly, view it on GitHub <#896 (comment)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AJKTDSQAFDZSGI76LRFVNF3WKUUDLANCNFSM6AAAAAASNVSWOY> . You are receiving this because you authored the thread.Message ID: ***@***.***>

[alejcas]

I see. Changed this in 5a9450a

[alejcas]

Will release a new version with this change soon. For the moment you can overwrite the event.save method

[aadslingerland]

Thank you! I was about to have a look at the source code anyway. Eager to learn...

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On Tue, 29 Nov 2022 at 10:26, Alejandro Casanovas ***@***.***> wrote: Will release a new version with this change soon. For the moment you can overwrite the event.save method — Reply to this email directly, view it on GitHub <#896 (reply in thread)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/AJKTDSRC3PDDNKK6QAQR2H3WKXD4RANCNFSM6AAAAAASNVSWOY> . You are receiving this because you authored the thread.Message ID: ***@***.***>