How to send netconf xml

[sak0]

example help.

May i send this xml packet with go-netconf like this:
Could you please give an example to do it?

<rpc message-id ="101" xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" xmlns:h3c="http://www.h3c.com/netconf/base:1.0"> <get> <filter type="subtree"> <top xmlns="http://www.h3c.com/netconf/data:1.0"> <VLAN> <VLANs> <VLANID> <ID></ID> <Description></Description> <Name></Name> <RouteIfIndex></RouteIfIndex> <UntaggedPortList></UntaggedPortList> <TaggedPortList></TaggedPortList> <Shared></Shared> </VLANID> </VLANs> </VLAN> </top> </filter> </get> </rpc>]]>]]>

[sak0]

package main

import (
	"fmt"
	"log"
	"time"

	"github.com/Juniper/go-netconf/netconf"
	"golang.org/x/crypto/ssh"
)

func doRpc(s *netconf.Session, xml string) {
	reply, err := s.Exec(netconf.RawMethod(xml))
	if err != nil {
		panic(err)
	}
	fmt.Printf("Reply: %+v", reply)
}

func main() {
	var sshconfig ssh.Config
	sshconfig.SetDefaults()
	cipherOrder := sshconfig.Ciphers
	sshconfig.Ciphers = append(cipherOrder, "aes128-cbc")
	
	sshConfig := &ssh.ClientConfig{
		Config:			sshconfig,
		User:            "admin",
		Auth:            []ssh.AuthMethod{ssh.Password("admin")},
		HostKeyCallback: ssh.InsecureIgnoreHostKey(),
		Timeout: 5 * time.Second,
	}

	s, err := netconf.DialSSH("10.0.2.2:830", sshConfig)

	if err != nil {
		log.Fatal(err)
	}

	defer s.Close()

	fmt.Println(s.ServerCapabilities)
	fmt.Println(s.SessionID)
	
	xml := `
<rpc message-id ="101" xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" xmlns:h3c="http://www.h3c.com/netconf/base:1.0">
<get>
   <filter type="subtree">
   <top xmlns="http://www.h3c.com/netconf/data:1.0">
<VLAN>
  <VLANs>
    <VLANID>
      <ID></ID>
      <Description></Description>
      <Name></Name>
      <RouteIfIndex></RouteIfIndex>
      <UntaggedPortList></UntaggedPortList>
      <TaggedPortList></TaggedPortList>
      <Shared></Shared>
    </VLANID>
  </VLANs>
</VLAN>
</top>
    </filter>
  </get>
</rpc>
	`
    fmt.Printf("%s", xml)
	
	doRpc(s, xml)
}

the code above will hung forever.

[nemith]

I am going to guess this may have to do with #89 and fix may be there.