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NaNMath.sqrt
Given a + bim, we could just return Base.sqrt(a + bim) since it can handle those values without throwing domain errors.
a + bim
Base.sqrt(a + bim)
Currently, NaNMath.sqrt(a + bim) will just yield a missing method error.
NaNMath.sqrt(a + bim)
The text was updated successfully, but these errors were encountered:
This is essentially the same as #66.
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Given
a + bim
, we could just returnBase.sqrt(a + bim)
since it can handle those values without throwing domain errors.Currently,
NaNMath.sqrt(a + bim)
will just yield a missing method error.The text was updated successfully, but these errors were encountered: