0125. Easy ｜Valid Palindrome.md

• 0125 - Valid Palindrome.md
• 难度：easy｜ 容易
• 相关知识点： String ｜ Two Pointers
• 题目链接： https://leetcode.com/problems/valid-palindrome/description/

class Solution:
    def isPalindrome(self, s: str) -> bool:
        left = 0
        right = len(s) - 1
        while left < right:
            while (left < right and not s[left].isalnum()):
                left += 1
            
            while (left < right and not s[right].isalnum()):
                right -= 1
            
            if s[left].lower() != s[right].lower():
                return False
            
            left += 1
            right -= 1
            
        return True