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hamilton.py
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hamilton.py
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class Hamilton():
def __init__(self, vertices):
self.graph = [[0 for column in range(vertices)] \
for row in range(vertices)]
self.V = vertices
self.path = []
''' Check if this vertex is an adjacent vertex
of the previously added vertex and is not
included in the path earlier '''
def isSafe(self, v, pos, path):
# Check if current vertex and last vertex
# in path are adjacent
if self.graph[path[pos - 1]][v] == 0:
return False
# Check if current vertex not already in path
for vertex in path:
if vertex == v:
return False
return True
# A recursive utility function to solve
# hamiltonian cycle problem
def hamCycleUtil(self, path, pos):
print("yo")
# base case: if all vertices are
# included in the path
if pos == self.V:
# Last vertex must be adjacent to the
# first vertex in path to make a cyle
if self.graph[path[pos - 1]][path[0]] == 1:
return True
else:
return False
# Try different vertices as a next candidate
# in Hamiltonian Cycle. We don't try for 0 as
# we included 0 as starting point in hamCycle()
for v in range(1, self.V):
if self.isSafe(v, pos, path) == True:
path[pos] = v
if self.hamCycleUtil(path, pos + 1) == True:
return True
# Remove current vertex if it doesn't
# lead to a solution
path[pos] = -1
return False
def hamCycle(self):
path = [-1] * self.V
''' Let us put vertex 0 as the first vertex
in the path. If there is a Hamiltonian Cycle,
then the path can be started from any point
of the cycle as the graph is undirected '''
path[0] = 0
if self.hamCycleUtil(path, 1) == False:
print("Solution does not exist\n")
return False
self.printSolution(path)
self.path = path
return True
def printSolution(self, path):
print
"Solution Exists: Following is one Hamiltonian Cycle"
for vertex in path:
print
vertex,
print
path[0], "\n"
'''
g1 = Hamilton(5)
g1.graph = [[0, 1, 0, 1, 0], [1, 0, 1, 1, 1],
[0, 1, 0, 0, 1, ], [1, 1, 0, 0, 1],
[0, 1, 1, 1, 0], ]
# Print the solution
g1.hamCycle();
'''