how could i use raw string replace object? when this object is null.

[dymasun]

In a case, I had read a string from redis, and then, I will deserialize it to be object, and as a field set into VO. Finally, it will be serialized as json string return to front endpoint. It effect the performance!
In Jackson API, there is a annotation named "JsonRawProperty", it can write string with out quote.
So, I have a object

public class People {
    public String name;
    public People kid;
    @JsonRawProperty
    public String firstKidSnapshot;
}

where is a papa named Bill, and he have a lovely kid named Tobby.
so, Bill's json is

{
    "name": "Bill",
    "kid": {
         "name": "Tobby"
    }
}

well, well, well.
It's my java code:

String kidSnapshot = "{\"name\": \"Tobby\"}"; // from redis
People bill = new People();
bill.name = "Bill";
bill.kidSnapshot = kidSnapshot;
String resultJson = objectMapper.writeValueAsString(bill);

So, How can I output that json? No need deserialize.

[JooHyukKim]

Can u elaborate further? I didnt understand what u need to achieve.

[dymasun]

this is my code

this is console output

and then, forget it.
What I want?
with these code

and output like this

how can i do this

[dymasun]

No need for deserialization

[JooHyukKim]

You want to NOT include kidssnapshot value right? If so, use JsonIgnore. There is plenty example on the web or ask ChatGPT.

[cowtowncoder]

Ugh. I hate screenshots, no copy-pasting etc. :-(

That said, I think he wants something like this:

public static class People {
  public String name;

  @JsonRawValue // not JsonRawProperty
  public String kid;
}

or

public static class People {
  public String name;

  @JsonIgnore
  public People kid;

  @JsonRawValue
  @JsonProperty("kid")
  public String kidSnapshot
}

Either way, marker @JsonRawValue just embeds given String value within JSON output, instead of escsaping as JSON String.

[JooHyukKim]

@dymasun please take a look here?
I think what @cowtowncoder's suggestions will do the job needed.