https://leetcode.com/problems/missing-ranges/
Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges.
Example:
Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99,
Output: ["2", "4->49", "51->74", "76->99"]
Time: O(N) && Space: O(1)
class Solution {
public List<String> findMissingRanges(int[] nums, int lower, int upper) {
List<String> res = new ArrayList<String>();
int next = lower;
for (int i = 0; i < nums.length; i++) {
if (nums[i] < next) {
continue;
}
else if (nums[i] == next) {
next++;
}
else { // nums[i] > next
res.add(getRange(next, nums[i] - 1));
next = nums[i] + 1;
}
}
if (next <= upper) {
res.add(getRange(next, upper));
}
return res;
}
String getRange(int n1, int n2) {
reutrn (n1 == n2) ? String.valueOf(n1) : String.format("%d->%d", n1, n2);
}
}